Conic Sections Question 52
Question: The point of intersection of the latus rectum and axis of the parabola $ y^{2}+4x+2y-8=0 $
Options:
A) (5/4, -1)
B) (9/4, -1)
C) (7/2, 5/2)
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
The required point is nothing but the focus of the parabola. Therefore $ {{(y+1)}^{2}}=-(4x-9)=-4( x-\frac{9}{4} ) $
$ S\equiv ( -1+\frac{9}{4},-1 ) $ or $ ( \frac{5}{4},-1 ) $ .
BETA
