[Pb. CET 2004]
A) $ 2y+3=0 $
B) $ 3y=2 $
C) $ 2y=3 $
D) $ 3y+2=0 $
Correct Answer: C
$ {{(x+2)}^{2}}=-2(y-2) $
Equation of latus rectum is $ y-2=-\frac{1}{2} $
therefore $ y=\frac{3}{2} $ .
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