Conic Sections Question 524
Question: The equation of the parabola whose vertex is (-1, -2), axis is vertical and which passes through the point (3, 6), is
Options:
A) $ x^{2}+2x-2y-3=0 $
B) $ 2x^{2}=3y $
C) $ x^{2}-2x-y+3=0 $
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
$ {{(x+1)}^{2}}=4a(y+2) $
Passes through (3, 6)
therefore $ 16=4a.8 $
therefore $ a=\frac{1}{2} $
therefore $ {{(x+1)}^{2}}=2(y+2) $
therefore $ x^{2}+2x-2y-3=0 $ .
BETA
