Conic Sections Question 531
Question: The focus of the parabola $ y^{2}=4y-4x $ is
[MP PET 1991]
Options:
A) (0, 2)
B) (1, 2)
C) (2, 0)
D) (2, 1)
Show Answer
Answer:
Correct Answer: A
Solution:
$ {{(y-2)}^{2}}=-4x+4 $
therefore $ {{(y-2)}^{2}}=-4(x-1) $
Vertex is (1,2) and focus = (0,2).