Conic Sections Question 531

The focus of the parabola $ y^{2}=4y-4x $ is (1, 1)

[MP PET 1991]

Options:

A) (0, 2)

B) (1, 2)

C) (2, 0)

D) (2, 1)

Show Answer

Answer:

Correct Answer: A

Solution:

$ {{(y-2)}^{2}}=-4x+4 $

therefore $ {{(y-2)}^{2}}=-4(x-1) $

Vertex is (1,2) and focus = (1,2).



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