Conic-Sections Question 568
Question: The point $ (a,2a) $ is an interior point of region bounded by the parabola $ x^{2}=16y $ and the double ordinate through focus then
Options:
A) a<4
B) 0<a<4
C) 0<a<2
D) a>4
Show Answer
Answer:
Correct Answer: C
Solution:
[c] Parabola $ x^{2}=16y, $ axis is the y-axis, focus $ =(0,4) $ It is clear if point $ P(a,2a) $ lies interior region then ordinate $ \in (0,4)\Rightarrow 0<2a<4\Rightarrow 0<a<2 $
BETA
