Conic Sections Question 62
Question: The equation of the tangent to the parabola $ y^{2}=4x+5 $ parallel to the line $ y=2x+7 $ is
[MNR 1979]
Options:
A) $ 2x-y-3=0 $
B) $ 2x-y+3=0 $
C) $ 2x+y+3=0 $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
Equation of parabola is $ Y^{2}=4X $ , where $ X=x+\frac{5}{4} $
Tangent parallel to $ Y=2X+7 $ is $ Y=2X+\frac{a}{m} $
therefore $ y=2( x+\frac{5}{4} )+\frac{1}{2} $
therefore $ y=2x+3 $ i.e., $ 2x-y+3=0 $ .
BETA
