Conic Sections Question 75
If the line $ y=mx+c $ touches the ellipse $ \frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1 $ , then $ c= $
[MNR 1975; MP PET 1994, 95, 99]
Options:
A) $ \pm \sqrt{b^{2}m^{2}+a^{2}} $
B) $ \pm \sqrt{a^{2}m^{2}+b^{2}} $
C) $ \pm \sqrt{b^{2}m^{2}-a^{2}} $
D) $ \pm \sqrt{a^{2}m^{2}-b^{2}} $
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Answer:
Correct Answer: A
Solution:
Since, here $ b $ and $ a $ are interchanged.
BETA
