Coordinate Geometry Question 103
Question: The equation of the locus of all points equidistant from the point (4,2) and the x-axis, is
[CEE 1993]
Options:
A) $ x^{2}+8x+4y-20=0 $
B) $ x^{2}-8x-4y+20=0 $
C) $ y^{2}-4y-8x+20=0 $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
$ {{(x-4)}^{2}}+{{(y-2)}^{2}}=y^{2}\Rightarrow x^{2}-8x-4y+20=0 $ .
BETA
