Coordinate Geometry Question 109
Question: A point moves in such a way that its distance from (1,-2) is always the twice from (-3,5), the locus of the point is
Options:
A) $ 3x^{2}+y^{2}+26x+44y-131=0 $
B) $ x^{2}+3y^{2}-26x+44y-131=0 $
C) $ 3(x^{2}+y^{2})+26x-44y+131=0 $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
$ {{(x-1)}^{2}}+{{(y+2)}^{2}}=2^{2}[{{(x+3)}^{2}}+{{(y-5)}^{2}}] $
$ \Rightarrow 3(x^{2}+y^{2})+26x-44y+131=0 $ .
BETA
