Coordinate Geometry Question 142
Question: If the points (1,1), (-1, -1) and $ (-\sqrt{3},k) $ are vertices of an equilateral triangle then the value of k will be
Options:
1
-1
C) $ \sqrt{3} $
D) $ -\sqrt{3} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ l^{2}=2^{2}+2^{2}=8={{(\sqrt{3}+1)}^{2}}+{{(k-1)}^{2}}\Rightarrow k=\sqrt{3}+1 $ .
BETA
