Coordinate Geometry Question 142

Question: If the points (1,1), (-1, -1) and $ (-\sqrt{3},k) $ are vertices of an equilateral triangle then the value of k will be

Options:

A) 1

B) -1

C) $ \sqrt{3} $

D) $ -\sqrt{3} $

Show Answer

Answer:

Correct Answer: C

Solution:

$ l^{2}=2^{2}+2^{2}=8={{(\sqrt{3}+1)}^{2}}+{{(k-1)}^{2}}\Rightarrow k=\sqrt{3} $ .