Coordinate Geometry Question 143
The area of the triangle enclosed by the straight lines $ x=0, \ y=0, \ \text{and} \ y=x $
$ y=0 $ and $ x+2y+3=0 $ in sq. unit is the area between the lines
Options:
A) $ \frac{9}{2} $
B) $ \frac{9}{4} $
C) $ \frac{3}{4} $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
$ \Delta =\frac{3^{2}}{2\times 1\times 2}=\frac{9}{4} $ . (Applying the formula given in the book)
BETA
