Coordinate Geometry Question 149
Circumcentre of the triangle formed by the lines $ y=x $, $ y=2x $ and $ y=3x+4 $ is
Options:
A) (6, 8)
B) (6, - 8)
C) (3, 4)
D) (- 3, - 4)
Show Answer
Answer:
Correct Answer: B
Solution:
$ x^{2}+y^{2}={{(x+4)}^{2}}+{{(y+8)}^{2}}\Rightarrow 8x+16y+80=0 $ and $ x^{2}+y^{2}={{(x+2)}^{2}}+{{(y+2)}^{2}}\Rightarrow 4x+4y+8=0 $ On simplification, we get $ y=-2 $ and $ x=-2 $ .
BETA
