Coordinate Geometry Question 155
Question: The orthocentre of the triangle formed by (0, 0), (8, 0), (4 6) is
[EAMCET 1991]
Options:
A) $ ( 4,\frac{8}{3} ) $
B) (3, 4)
C) (4, 3)
D) (-3, 4)
Show Answer
Answer:
Correct Answer: A
Solution:
Let the vertices of the triangle be O(0, 0) $ A(8,0), $
$ B(4,6) $ . The equation of an altitude through O and perpendicular to AB is $ y=\frac{2}{3}x $ and the equation of an altitude through $ A(8,0) $ and perpendicular to OB is $ 3y=-2x+16 $ . The two altitudes intersect at $ ( 4,\frac{8}{3} ) $ .
BETA
