Coordinate Geometry Question 158
Question: Orthorcentre of triangle with vertices (0, 0), (3, 4) and (4, 0) is
[IIT Screening 2003]
Options:
A) $ ( 3,\frac{5}{4} ) $
B) (3, 12)
C) $ ( 3,\frac{3}{4} ) $
D) (3, 9)
Show Answer
Answer:
Correct Answer: C
Solution:
$ BD\bot AC $ . Slope of $ BD=-\frac{3}{4} $ Equation of $ BD $ , $ 3x+4y-12=0;AE\bot BC $ …..(i)
Slope of $ AE=\frac{1}{4} $ Equation of AE, $ x-4y=0 $ …..(ii)
From equation (i) and (ii),
$ x=3,y=\frac{3}{4} $ orthocentre of the triangle is $ ( 3,\frac{3}{4} ) $
BETA
