Coordinate Geometry Question 159
Question: The orthocentre of triangle formed by lines $ 4x-7y+10=0, $
$ x+y=5 $ and $ 7x+4y=15 $ is
[IIT 1969, 76]
Options:
A) (1, 2)
B) (1, -2)
C) (-1, -2)
D) (-1, 2)
Show Answer
Answer:
Correct Answer: A
Solution:
Orthocentre of right angled triangle is same as the vertex of right angle. Therefore, point of intersection of $ 7x+4y-15=0 $ and $ 4x-7y+10=0 $ is (1, 2).
BETA
