Coordinate Geometry Question 164
Question: The orthocentre of the triangle formed by the lines $ x+y=1,2x+3y=6 $ and $ 4x-y+4=0 $ lies in quadrant
[IIT 1985]
Options:
A) First
B) Second
C) Third
D) Fourth
Show Answer
Answer:
Correct Answer: A
Solution:
On solving the equations, we get the two vertices (-3, 4) and $ ( \frac{-3}{7},\frac{16}{7} ) $ . Also perpendicular passes through vertices are $ x+4y=13 $ and $ 7x-7y=-19 $ . Solving these lines, we get the orthocentre $ ( \frac{3}{7},\frac{22}{7} ) $ i.e. in first quadrant.
BETA
