Coordinate Geometry Question 167
Question: The orthocentre of the triangle with vertices $ ( 2,\frac{\sqrt{3}-1}{2} ) $ , $ ( \frac{1}{2},-\frac{1}{2} ) $ and $ ( 2,-\frac{1}{2} ) $ is
[IIT 1993]
Options:
A) $ ( \frac{3}{2},\frac{\sqrt{3}-3}{6} ) $
B) $ ( 2,-\frac{1}{2} ) $
C) $ ( \frac{5}{4},\frac{\sqrt{3}-2}{4} ) $
D) $ ( \frac{1}{2},-\frac{1}{2} ) $
Show Answer
Answer:
Correct Answer: B
Solution:
Here, the given triangle is a right angled triangle at the vertex $ ( 2,-\frac{1}{2} ) $ .
Hence the orthocentre is at $ ( 2,\frac{-1}{2} ) $ .
BETA
