Coordinate Geometry Question 171
Point of intersection of the diagonals of a square is at origin and coordinate axes are drawn along the diagonals. If the side is of length a, then one which is not the vertex of the square is
Options:
A) $ (a\sqrt{2},0) $
B) $ ( 0,\frac{a}{\sqrt{2}} ) $
C) $ ( \frac{a}{\sqrt{2}},0 ) $
D) $ ( -\frac{a}{\sqrt{2}},0 ) $
Show Answer
Answer:
Correct Answer: A
Solution:
Obviously, from right angled triangle BOA $ OA=OB=\frac{a}{\sqrt{2}} $
Hence the vertex $ (a\sqrt{2},0) $ is not the vertex of square.
BETA
