Coordinate Geometry Question 24
Question: The equation of the locus of a point whose distance from (a, 0) is equal to its distance from y-axis, is
[MP PET 1986]
Options:
A) $ y^{2}-2ax=a^{2} $
B) $ y^{2}-2ax+a^{2}=0 $
C) $ y^{2}+2ax+a^{2}=0 $
D) $ y^{2}+2ax=a^{2} $
Show Answer
Answer:
Correct Answer: B
Solution:
Let the point be $ (h,k), $ So, $ {{(h-a)}^{2}}+{{(k-0)}^{2}}=h^{2} $
$ \Rightarrow h^{2}+a^{2}-2ah+k^{2}=h^{2} $
Hence locus is $ y^{2}-2ax+a^{2}=0 $ .
BETA
