Coordinate Geometry Question 36
Question: If the vertices of triangle are (0,2), (1,0) and (3,1), then the triangle is
Options:
A) Equilateral triangle
B) Isosceles triangle
C) Right-angled
D) Isosceles right angled
Show Answer
Answer:
Correct Answer: D
Solution:
Here $ A(0,2),B(1,0) $ and $ C(3,1). $
Therefore, $ AB=\sqrt{1+4}=\sqrt{5},BC=\sqrt{4+1}=\sqrt{5} $ and $ xz+3y=9 $ It is clear that $ {{(AC)}^{2}}={{(AB)}^{2}}+{{(BC)}^{2}} $
Hence, the triangle is an isosceles right-angled triangle.
BETA
