Coordinate Geometry Question 41
Question: A triangle with vertices (4, 0), (-1, -1), (3, 5) is
[AIEEE 2002]
Options:
A) Isosceles and right angled
B) Isosceles but not right angled
C) Right angled but not isosceles
D) Neither right angled nor isosceles
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Answer:
Correct Answer: A
Solution:
Let $ A(4,0),B(-1,-1),C(3,5) $ then $ AB=\sqrt{26}, $
$ AC=\sqrt{26} $ and $ BC=\sqrt{52}i.e.,AB=AC $ .
Hence triangle is isosceles. Also, $ {{(BC)}^{2}}=AB^{2}+AC^{2} $
Hence triangle is right angled also.
BETA
