Coordinate Geometry Question 5
Question: The incentre of the triangle with vertices $ (1,\sqrt{3}) $ , (0, 0) and (2, 0) is
[IIT Screening 2000]
Options:
A) $ ( 1,\frac{\sqrt{3}}{2} ) $
B) $ ( \frac{2}{3},\frac{1}{\sqrt{3}} ) $
C) $ ( \frac{2}{3},\frac{\sqrt{3}}{2} ) $
D) $ ( 1,\frac{1}{\sqrt{3}} ) $
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Answer:
Correct Answer: D
Solution:
Clearly, the triangle is equilateral. So, the incentre is the same as the centroid.
$ \therefore $ Incentre $ =( \frac{1+0+2}{3},\frac{\sqrt{3}+0+0}{3} )=( 1,\frac{1}{\sqrt{3}} ) $ .
BETA
