Coordinate Geometry Question 60
Question: If the points (0, 0), $ (2,2\sqrt{3}) $ and (a, b) be the vertices of an equilateral triangle, then $ (a,b)= $
Options:
A) (0, - 4)
B) (0, 4)
C) (4, 0)
D) (- 4, 0)
Show Answer
Answer:
Correct Answer: C
Solution:
$ l=\sqrt{4+12}=4\Rightarrow a^{2}+b^{2}=16 $ and $ {{(a-2)}^{2}}+{{(b-2\sqrt{3})}^{2}}=16\Rightarrow a+\sqrt{3}b=4 $
Hence $ (a,b)=(4,0) $ .
BETA
