Coordinate Geometry Question 78
Question: The point on y-axis equidistant from the points (3, 2) and (-1, 3) is
Options:
A) (0, -3)
B) (0, -3/2)
C) (0, 3/2)
D) (0, 3)
Show Answer
Answer:
Correct Answer: B
Solution:
Point on y-axis is (0, b), therefore by given condition $ {{(0-3)}^{2}}+{{(b-2)}^{2}}={{(0+1)}^{2}}+{{(b-3)}^{2}} $
$ \Rightarrow 9+b^{2}+4-4b=1+b^{2}+9-6b\Rightarrow b=-\frac{3}{2} $
Hence the point is $ ( 0,-\frac{3}{2} ) $ .
BETA
