Coordinate Geometry Question 94
Question: The locus of a point which moves so that it is always equidistant from the point A(a, 0) and B (- a, 0) is
[MP PET 1984]
Options:
A) A circle
B) Perpendicular bisector of the line segment AB
C) A line parallel to x-axis
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
Let point be (h, k) then, $ {{(h-a)}^{2}}+k^{2}={{(h+a)}^{2}}+k^{2} $
$ \Rightarrow 4ha=0\Rightarrow h=0. $
Hence x = 0.
BETA
