Definite Integration Question 103

Question: The value of $ \int_0^{1}{(1+{e^{-x^{2}}})}dx= $

[IIT 1981]

Options:

A) $ -1 $

B) 2

C) $ 1+{e^{-1}} $

D) None of these

Show Answer

Answer:

Correct Answer: D

Solution:

$ \int_0^{1}{dx+\int_0^{1}{{e^{-x^{2}}}dx=1+\int_0^{1}{{e^{-x^{2}}}dx}}} $ , but $ \int_0^{1}{{e^{-x^{2}}}}dx $ is not integrable.