Definite Integration Question 103
Question: The value of $ \int_0^{1}{(1+{e^{-x^{2}}})}dx= $
[IIT 1981]
Options:
A) $ -1 $
B) 2
C) $ 1+{e^{-1}} $
D) None of these
Show Answer
Answer:
Correct Answer: D
Solution:
$ \int_0^{1}{dx+\int_0^{1}{{e^{-x^{2}}}dx=1+\int_0^{1}{{e^{-x^{2}}}dx}}} $ , but $ \int_0^{1}{{e^{-x^{2}}}}dx $ is not integrable.