[MP PET 1990]
A) 0
B) $ \frac{1}{2} $
C) $ \frac{1}{3} $
D) $ \frac{1}{4} $
Correct Answer: C
$ \int_0^{1}{{e^{2\log x}}dx=\int_0^{1}{{e^{\log x^{2}}}}dx=\int_0^{1}{x^{2}dx=[ \frac{x^{3}}{3} ]_0^{1}=\frac{1}{3}}} $ .
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