Definite Integration Question 167
Question: Area bounded by $ y=x\sin x $ and $ x- $ axis between $ x=0 $ and $ x=2\pi , $ is
[Roorkee 1981; RPET 1995]
Options:
0
B) $ 2\pi \ \text{sq. unit} $
C) $ \pi , \text{sq. unit}$
D) $ 4\pi , \text{sq. unit} $
Show Answer
Answer:
Correct Answer: D
Solution:
Required area is $ A_1+A_2=\int_0^{\pi }{ydx}+| \int _{\pi }^{2\pi }{ydx} |=4\pi \text{ sq. }unit $
BETA
