Definite Integration Question 173
Question: The area enclosed by the curve $ x^{2}y=36, $ the x-axis and the lines x = 6 and x = 9 is
Options:
A) 6
B) 1
C) 4
D) 2
Show Answer
Answer:
Correct Answer: D
Solution:
[d] $ y=\frac{36}{x^{2}},x=6,x=9 $ Desired area $ =\int\limits_6^{9}{\frac{36}{x^{2}}dx} $
$ =-36[ \frac{1}{9}-\frac{1}{6} ]=2 $
BETA
