[MP PET 1996; Pb. CET 2002]
A) $ -1 $
B) 0
C) 1
D) $ \pi $
Correct Answer: B
$ \int_0^{\pi }{{{\cos }^{3}}xdx=\int_0^{2.\frac{\pi }{2}}{{{\cos }^{3}}xdx=0}} $ , $ {\because {{\cos }^{3}}(\pi -x)=-{{\cos }^{3}}x} $ .
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