[Karnataka CET 2002]
A) 3
B) 2
C) 1
D) 0
Correct Answer: D
$ I=\int _{1}^{3}{(x-1)(x-2)(x-3)dx} $ .
$ I=\int _{1}^{3}{(x^{3}-6x^{2}+11x-6)dx=[ \frac{x^{4}}{4}-\frac{6x^{3}}{3}+\frac{11x^{2}}{2}-6x ] _{1}^{3}=0.} $
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