Definite Integration Question 182
Question: Area bounded by the parabola $ y^{2}=4ax $ and its latus rectum is
[RPET 1997, 2000, 02]
Options:
A) $ \frac{2}{3}a^{2} $ sq. unit
B) $ \frac{4}{3}a^{2} $ sq. unit
C) $ \frac{8}{3}a^{2} $ sq. unit
D) $ \frac{3}{8}a^{2} $ sq. unit
Show Answer
Answer:
Correct Answer: C
Solution:
Area = $ 2\int_0^{a}{ydx=2\int_0^{a}{\sqrt{4ax}}dx} $
$ 2\times 2\sqrt{a}\times \frac{2}{3}| {x^{3/2}} |_0^{a}=\frac{8}{3}a^{2} $ sq. unit.
BETA
