[MP PET 1990]
A) $ -2 $
B) $ -1 $
C) 0
D) 2
Correct Answer: C
Let $ f(x)=x^{17}{{\cos }^{4}}x $
$ f(-x)={{(-x)}^{17}}{{{ \cos (-x) }}^{4}}=-f(x) $
Therefore, $ \int _{-1}^{1}{x^{17}{{\cos }^{4}}xdx=0} $ .
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