Definite Integration Question 243
Question: The area between the curve $ y^{2}=4ax, $ x-axis and the ordinates $ x=0 $ and $ x=a $ is
[RPET 1996]
Options:
A) $ \frac{4}{3}a^{2} $
B) $ \frac{8}{3}a^{2} $
C) $ \frac{2}{3}a^{2} $
D) $ \frac{5}{3}a^{2} $
Show Answer
Answer:
Correct Answer: B
Solution:
Required area $ =2\int_0^{a}{\sqrt{4ax}dx} $
$ =4\sqrt{a}\times \frac{2}{3}[{x^{3/2}}]_0^{a}=\frac{8\sqrt{a}}{3}.a\sqrt{a}=\frac{8}{3}a^{2} $ .
BETA
