Definite Integration Question 257
Question: $ \int _{-\pi /2}^{\pi /2}{\sqrt{\frac{1}{2}(1-\cos 2x)}}dx= $
Options:
A) 0
B) 2
C) $ \frac{1}{2} $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
$ \int _{-\pi /2}^{\pi /2}{\sqrt{\frac{1}{2}(1-\cos 2x)}}dx=2\int_0^{\pi /2}{|\sin x|dx} $
= $ 2[-\cos x]_0^{\pi /2}=2[ -\cos ( \frac{\pi }{2} )+\cos 0 ]=2 $ .
BETA
