Definite Integration Question 273
Question: The area enclosed by the parabolas $ y=x^{2}-1 $ and $ y=1-x^{2} $ is
[AMU 1999]
Options:
1/3
2/3
4/3
8/3
Show Answer
Answer:
Correct Answer: D
Solution:
Given parabolas are $ x^{2}=1+y $ , $ x^{2}=1-y $
Required area $ =4\int_0^{1}{(1-x^{2})dx} $
$ =4\left[ x-\frac{x^{3}}{3} \right]_0^{1}=\frac{8}{3} $
BETA
