Definite Integration Question 302
Question: The area of bounded by $ y=e^{x},y={e^{-x}} $ and the straight line $ x=1 $ is
[Karnataka CET 1999]
Options:
A) $ e+\frac{1}{e} $
B) $ e-3 $
C) $ e+\frac{1}{e}-2 $
D) $ e+\frac{1}{e}+2 $
Show Answer
Answer:
Correct Answer: C
Solution:
Given equations of curves $ y=e^{x};y={e^{-x}} $ and straight line $ x=1 $
We know that area of the figure bounded by the curves and straight line
$ =\int_0^{1}{(e^{x}-{e^{-x}})dx=[e^{x}+{e^{-x}}] _0^{1}=e+\frac{1}{e}-2.} $
BETA
