Definite Integration Question 304
Question: The volume of the solid formed by rotating the area enclosed between the curve $ y=x^{2} $ and the line $ y=1 $ about $ y=1 $ is (in cubic units
[UPSEAT 2003]
Options:
A) $ 9\pi /5 $
B) $ 4\pi /3 $
C) $ 8\pi /3 $
D) $ 7\pi /5 $
Show Answer
Answer:
Correct Answer: B
Solution:
Volume of the solid formed by rotating the area enclosed between the curve $ y=x^{2} $ and line $ y=1 $ will be $ \int_0^{1}{2\pi xdy} $ = $ 2\int_0^{1}{\pi \sqrt{y}dy} $ = $ \frac{4\pi }{3}[{y^{3/2}}]_0^{1}=\frac{4\pi }{3} $ .
BETA
