Definite Integration Question 322
Question: The area of the region bounded by the curve $ 9x^{2}+4y^{2}-36=0 $ is
[Karnataka CET 2005]
Options:
A) $ 9\pi $
B) $ 4\pi $
C) $ 36\pi $
D) $ 6\pi $
Show Answer
Answer:
Correct Answer: D
Solution:
$ 9x^{2}+4y^{2}=36 $
therefore $ \frac{x^{2}}{4}+\frac{y^{2}}{9}=1 $ , which is equation of an ellipse. Remember area enclosed by ellipse is $ \pi ab $ i.e., $ \pi2.3=6\pi $ .
BETA
