[DCE 1999]
A) 5/2
B) 1/2
C) 3/2
D) 7/2
Correct Answer: A
$ I=\int _{-1}^{2}{|x|dx} $
$ =\int _{-1}^{0}{-xdx}+\int_0^{2}{xdx} $
$ =-[ \frac{x^{2}}{2} ] _{-1}^{0}+[ \frac{x^{2}}{2} ]_0^{2} $
$ =-[ 0-\frac{1}{2} ]+[2] $
$ =2+\frac{1}{2}=\frac{5}{2} $ .
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