Definite Integration Question 334
Question: The area of the region (in the square unit) bounded by the curve $ x^{2}=4y, $ line $ x=2 $ and x-axis is
[MP PET 2002]
Options:
A) 1
B) $ \frac{2}{3} $
C) $ \frac{4}{3} $
D) $ \frac{8}{3} $
Show Answer
Answer:
Correct Answer: B
Solution:
Given $ x^{2}=4y $
Shaded area $ =\int_0^{2}{\frac{x^{2}}{4}dx} $
$ =\frac{1}{12}[x^{3}]_0^{2}=\frac{8}{12}=\frac{2}{3} $ .
BETA
