Definite Integration Question 355
Question: Area bounded by parabola $ y^{2}=x $ and straight line $ 2y=x $ is
[MP PET 1996]
Options:
A) $ \frac{4}{3} $
B) 1
C) $ \frac{2}{3} $
D) $ \frac{1}{3} $
Show Answer
Answer:
Correct Answer: A
Solution:
$ y^{2}=x $ and $ 2y=x\Rightarrow y^{2}=2y\Rightarrow y=0,2 $
$ \therefore $ Required area $ =\int_0^{2}{(y^{2}-2y)dy=( \frac{y^{3}}{3}-y^{2} )_0^{2}=\frac{4}{3}} $ sq. unit.
BETA
