A) $ \frac{1}{4} $
B) $ \frac{1}{3} $
C) $ \frac{1}{2} $
D) None of these
Correct Answer: A
$ \frac{1}{2}\int_0^{\pi /8}{{{\sec }^{2}}2xdx=\frac{1}{4}[\tan 2x]_0^{\pi /8}}=\frac{1}{4}[1]=\frac{1}{4} $ .
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