Definite Integration Question 373
Question: $ \int_0^{1}{{{\cos }^{-1}}xdx=} $
[DSSE 1988]
Options:
A) 0
B) 1
C) 2
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
$ \int_0^{1}{{{\cos }^{-1}}xdx=[ x{{\cos }^{-1}}x-\sqrt{1-x^{2}} ]}_0^{1}=1 $ .