Definite Integration Question 373

Question: $ \int_0^{1}{{{\cos }^{-1}}xdx=} $

[DSSE 1988]

Options:

A) 0

B) 1

C) 2

D) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

$ \int_0^{1}{{{\cos }^{-1}}xdx=[ x{{\cos }^{-1}}x-\sqrt{1-x^{2}} ]}_0^{1}=1 $ .