[Karnataka CET 2004]
0
2
4
Correct Answer: C
$ \int _{-1}^{1}{|1-x|}dx=\int _{-1}^{0}{(1-x)dx}+\int _{0}^{1}{(x-1)dx}=[ x-\frac{x^{2}}{2} ] _{-1}^{0}+[ \frac{x^{2}}{2}-x ] _{0}^{1}= \frac{3}{2}+\frac{1}{2}=2 $
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