Definite Integration Question 424
Question: If the area above the x-axis, bounded by the curves $ y=2^{kx} $ and $ x=0 $ and $ x=2 $ is $ \frac{3}{\ln 2}, $ then the value of k is
[Orissa JEE 2003]
Options:
A) $ \frac{1}{2} $
1
C) $ -1 $
2
Show Answer
Answer:
Correct Answer: B
Solution:
$ \int _{0}^{2}{2^{kx}dx=\frac{2^{2k}-1}{k\log 2}\Rightarrow 2^{2k}-1=3k\log 2} $ . Now check from options, only satisfies the above condition.
BETA
