Definite Integration Question 43
Question: $ \int _{-2}^{2}{|x|dx=} $
[MP PET 2000]
Options:
A) 0
B) 1
C) 2
D) 4
Show Answer
Answer:
Correct Answer: D
Solution:
$ I=\int _{-2}^{2}{|x|dx} $
$ =-\int _{-2}^{0}{xdx+\int_0^{2}{xdx}} $
$ =-[ \frac{x^{2}}{2} ] _{-2}^{0}+[ \frac{x^{2}}{2} ] _0^{2} $
$ =-(-2)+(2)=4 $ .