Definite Integration Question 43

Question: $ \int _{-2}^{2}{|x|dx=} $

[MP PET 2000]

Options:

A) 0

B) 1

C) 2

D) 4

Show Answer

Answer:

Correct Answer: D

Solution:

$ I=\int _{-2}^{2}{|x|dx} $

$ =-\int _{-2}^{0}{xdx+\int_0^{2}{xdx}} $

$ =-[ \frac{x^{2}}{2} ] _{-2}^{0}+[ \frac{x^{2}}{2} ] _0^{2} $

$ =-(-2)+(2)=4 $ .