Definite Integration Question 436
Question: The area bounded by the curves $ x=y^{2} $ and $ x=\frac{2}{1+y^{2}} $ is
Options:
A) $ \pi -\frac{2}{3} $
B) $ \pi +\frac{2}{3} $
C) $ -\pi -\frac{2}{3} $
D) none of these
Show Answer
Answer:
Correct Answer: A
Solution:
[a] Solving curves, we get point of intersection $ (1,\pm 1). $ Required area is $ 2\int_0^{1}{( \frac{2}{1+y^{2}}-y^{2} )dy=\pi -\frac{2}{3}} $
BETA
