Definite Integration Question 437
Question: The area of the region in 1st quadrant bounded by the y-axis, y = $ \frac{x}{4} $ , y = 1 + $ \sqrt{x} $ , and $ y=\frac{2}{\sqrt{x}} $ is
Options:
1
2
C) $ \pi $
D) 2 $ \pi $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] The required area is shown by shaded portion in the figure.
The required area is $ A=\int\limits _{-\pi /2}^{\pi /2}{| \sin y |dy=2\int\limits_0^{\pi /2}{\sin y, dy}=2} $
BETA
