[SCRA 1996; Pb. CET 2003]
A) $ \infty $
B) 0
C) 1
D) $ \log (1+e) $
Correct Answer: C
$ I=\int_1^{e}{\frac{1}{x}dx} $
$ =[\log x]_1^{e}={\log _{e}}e-\log 1=1 $ .
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